In a survey of 40 students, it was found that to take Mathematics, 17 take Music, 11 take History, I take Mathematis and History, 12 take Mathomatics and Music, Atake Music and History and 2 take all three courses. I find the number that take exactly one of the three courses.
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Step-by-step explanation:
(i) 11−5−4+3=5(3 removed twice)
(ii) 4−3=1
(iii) only maths =15−9−5+3 =4
only phy =12−9−4+3=2
only chem =5⇒Total=11
(iv) Atleast one =11+9+5+4−2(3)=29−6=23
⇒ None =25−23=2
(v) 23
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