Question

in a survey of 400 employees of a company it was found 180 employees liked the lunch pack provided by the company while the rest didn't if one employee chosen at random what is the probability of of the chosen employee will 1) dislike the lunch 2) likes the lunch​

Answer 1

Answer:

PROBABILITY = no. of favourable outcome

total no. of outcome

total no. of outcome = 400

no. of employee who liked the lunch = 180

no. of employee who don't liked the lunch = 400 - 180 = 220

1. P( who dislike the lunch ) = 220/400

2.P(who liked the lunch ) = 180/400

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