In a survey of 400 students in a school, 100 were listed as taking apple juice, 150 as taking orange juice and 75 were listed as taking both apple as well as orange juice. Find how many students were taking neither apple juice nor orange juice.
ch- sets class 11th
ans- 225 I want sol. please
Answers
Answered by
1
Answer:
Number of students taking apple juice = n(A) =100
number of students taking orange juice = n(O) = 150
number of students taking both = n(A ∩O) =75
number of students taking either apple or orange juice = n(A∪O)
n(A∪O) = n(A)+n(O)-n(A∩O)
=100+150-75
=100+75
=175
Answered by
2
225 Students
Total Number of students in the school = 400 (U)
Number of students that like apple juice = 100 (A)
Number of students that like orange juice = 150 (B)
Number of students that like both apple and orange juice = n (A ∩ B) = 75
n(A ∩ B) = n(A U B)
= n(u) - n(A U B)
= n(u) - [n(A) + n(B) -n(A ∩ B)]
Substituting the values in this formula we get:
= 400 - [100 + 150 - 75]
= 400 - 175
= 225
Number of students who do not like apply juice nor orange juice is 225 students.
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