Question

in a survey of 5000 persons in the town it was found that 45 percentage of the persons no language a 25% h no language be 10% changed no language c v percentage no languages a and b for percentage no languages b and c and 4% h no languages a and see if three percentage of the person know all three languages find the number of persons who knows onely language a​

Answer 1

Answer:

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Step-by-step explanation:

Those who know language a = 45% x 5000

= 2250

Those who know language b 25% x 5000

= 1250

Those who know languages a and b = 5% x 5000

= 250

Those who know a alone = 2250 - 250

= 2000

Answer 2

Answer:

n(A) = 45% of 5000

similarly, n(B) = 1250, n(C) = 500, n(A∩B) = 250, n(B∩C) = 200, n(C∩A) = 200 and

n(A∩B∩C) = 150

the number of persons who knows only language A

= n(A) - n(A∩B) - n(A∩C) + n(A∩B∩C)

= 2250-250-200+150

= 1950