In a survey of 60 persons it was found that. 25 read news week, 26 read times and 26 read fortune. Further 9 read both
newsweek and fortune, 11 read both newsweek and times, 8 read both time and fortune, 8 read none of this
Find the number of people who read all the three magazines
Answers
Answer:
not sure but can be 28 ...........
Answer:
3
Step-by-step explanation:
No. of persons involved in survey = U = 60
No. of people read news week = n (w) = 25
No. of people read times = n (t) = 26
No. of people read fortune = n (f) = 26
No. of people read both newsweek and fortune = n ( wnf ) = 9
No. of people read both newsweek and times = n ( w n t ) = 11
No. of people read both time and fortune = n (tnf) = 8
No. of people read non = n ( wntnf ) ' = 8
No. of people read all = n(wntnf) = ?
U = n ( w U t U f ) + n ( wntnf ) '
=> 60 = n ( w U t U f ) + 8
=> n ( w U t U f ) = 60 - 8
=> n ( w U t U f ) = 52 = no. of people read news
n ( wUtUf ) = n(w) + n(t) + n(f) - n(wnf) - n(wnt) - n(tnf) + n(wntnf)
=> 52 = 25 + 26 + 26 - 9 - 11 - 8 + n(wntnf)
=> 52 = 49 + n(wntnf)
=> n(wntnf) = 52 - 49
=> n(wntnf) = 3