Math, asked by prvendarkumar0305200, 1 month ago

In a survey of a college it was found that 49% like reading maths , 52% like reading physics and 50% like ready chemistry and also, 20% like reading math and physics both , 21% like reading math and chemistry both and 23% like physics and chemistry both. If 5% like reading none of these 3 subjects ,then find out that what percentage of student like only one subject math , physics and chemistry?​

Answers

Answered by sulekhaverma8829
0

Answer:

I have not no big thing

Answered by amitnrw
1

Given :  a survey of a college

To Find : what percentage of student like only one subject math , physics and chemistry ​

Solution:

n(M) = 49%

n(P) = 52 %

n(C) = 50 %

n( M ∩ P) = 20 %

n( M ∩ C) = 21 %

n ( P ∩C ) = 23 %

n( P ∩ M ∩ C) =  ?

none = 5 %

Total = 100 %

=> Total = n(M) + n(P)  + n(C)  - n( M ∩ P) - n( M ∩ C) - n( C∩ P) + n( P ∩ M ∩ C)  + none

=> 100 = 49 + 52 + 50 - 20 - 21 - 23 +  n( P ∩ M ∩ C)   + 5

=> n( P ∩ M ∩ C)   = 8

n( P ∩ M ∩ C)   = 8 %

Only maths =  n(M) - n( M ∩ P) - n( M ∩ C) + n( P ∩ M ∩ C)

Only P =  n(P) - n( M ∩ P) - n( P ∩ C) + n( P ∩ M ∩ C)

Only C = n(C) - n( M ∩ C) - n( P ∩ C) + n( P ∩ M ∩ C)

only one subject = n (M ) + n(P) + n(C) - 2 ( n( M ∩ P) + n( M ∩ C) + n( C∩ P) )

+ 3 n( P ∩ M ∩ C)

= 49 + 52 + 50  - 2(20 + 21 + 23) + 3 (8)

= 151  - 128 + 24

= 47

Hence 47 %  of student like only one subject math , physics and chemistry

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