Question

In a swimming competition, Peter swam 600m and Gabriel swam 2km .What is the ratio of Peter’s distance to Gabriel’s? Give your answer in its simplest form.b. Express the ratio 20cm to 15m in the form 1: n

c. Express the ratio 60 cm to 20 m in the form 1 : n

Answer 1

Answer:

Letdistance=d

The angle made with the upstream=θ

Therefore,

90−θ=Angle made with the normal stream

Hence,

Shortest Time Method:

Time taken, t=

v

d

Shortest distance method:

Time taken = t'=

vcos(90−θ)

d

=

vsinθ

d

Therefore, required ratio

=

t

′

t

=

v

d

sinθ

v

d

=sinθ