Question

. In a symmetrical distribution if Q1=4, Q3=12 then median is:​

Answer 1

The median is 8

Given :

In a symmetrical distribution Q₁ = 4 , Q₃ = 12

To find :

The median

Formula :

For a symmetrical distribution

$\displaystyle \sf{The \: median = \frac{1}{2}( Q_1 + Q_3 )}$

Solution :

Step 1 of 2 :

Write down the given data

Here it is given that in a symmetrical distribution Q₁ = 4 , Q₃ = 12

Step 2 of 2 :

Find the median

The median

$\displaystyle \sf{ = \frac{1}{2}( Q_1 + Q_3 )}$

$\displaystyle \sf{ = \frac{1}{2}( 4 +12 )}$

$\displaystyle \sf{ = \frac{1}{2} \times 16}$

$\displaystyle \sf{ = 8}$

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