Physics, asked by ektarao8887, 11 months ago

In a system,executing a non flow process, the work and heat per degree change of temperature are given by dq/dt=200W-S/°C and dq/dt= 160J/°C, what will be the change of internal energy of the system when its temperature changes from T1=55°C to T2=95°C​

Answers

Answered by abhi178
0

change of internal energy of the system when its temperature changes from T1=55°C to T2=95°C is 1600 J

in a system, executing a non flow process.

first we should understand what is non flow process ?

non flow process is a process in which no mass transfer takes place between system and surroundings.

A non flow process occurs in a closed system that usually undergoes displacement work (i.e., W = p∫dv)

from first law of thermodynamics,

Q = W + U

differentiating with respect to time,

dQ/dT = dW/dT + dU/dT

given, dQ/dT = 200 W.s/°C = 200 J/°C

dW/dT = 160 J/°C

so, dU/dT = 200 - 160 = 40 J/°C

so, change of internal energy, U = dU/dT × ∆T

= 40 J/°C × (95°C- 55°C)

= 40J/°C × 40°C

= 1600 J

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Answered by Anonymous
0

\huge\bold\purple{Answer:-}

in a system, executing a non flow process.

first we should understand what is non flow process ?

non flow process is a process in which no mass transfer takes place between system and surroundings.

A non flow process occurs in a closed system that usually undergoes displacement work (i.e., W = p∫dv)

from first law of thermodynamics,

Q = W + U

differentiating with respect to time,

dQ/dT = dW/dT + dU/dT

given, dQ/dT = 200 W.s/°C = 200 J/°C

dW/dT = 160 J/°C

so, dU/dT = 200 - 160 = 40 J/°C

so, change of internal energy, U = dU/dT × ∆T

= 40 J/°C × (95°C- 55°C)

= 40J/°C × 40°C

= 1600 J

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