In a system,executing a non flow process, the work and heat per degree change of temperature are given by dq/dt=200W-S/°C and dq/dt= 160J/°C, what will be the change of internal energy of the system when its temperature changes from T1=55°C to T2=95°C
Answers
change of internal energy of the system when its temperature changes from T1=55°C to T2=95°C is 1600 J
in a system, executing a non flow process.
first we should understand what is non flow process ?
non flow process is a process in which no mass transfer takes place between system and surroundings.
A non flow process occurs in a closed system that usually undergoes displacement work (i.e., W = p∫dv)
from first law of thermodynamics,
Q = W + U
differentiating with respect to time,
dQ/dT = dW/dT + dU/dT
given, dQ/dT = 200 W.s/°C = 200 J/°C
dW/dT = 160 J/°C
so, dU/dT = 200 - 160 = 40 J/°C
so, change of internal energy, U = dU/dT × ∆T
= 40 J/°C × (95°C- 55°C)
= 40J/°C × 40°C
= 1600 J
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in a system, executing a non flow process.
first we should understand what is non flow process ?
non flow process is a process in which no mass transfer takes place between system and surroundings.
A non flow process occurs in a closed system that usually undergoes displacement work (i.e., W = p∫dv)
from first law of thermodynamics,
Q = W + U
differentiating with respect to time,
dQ/dT = dW/dT + dU/dT
given, dQ/dT = 200 W.s/°C = 200 J/°C
dW/dT = 160 J/°C
so, dU/dT = 200 - 160 = 40 J/°C
so, change of internal energy, U = dU/dT × ∆T
= 40 J/°C × (95°C- 55°C)
= 40J/°C × 40°C
= 1600 J