In a system with 2 coaxial disks, one disk initially rotates at a speed of 120 revolutions per second. The orbital torque of the disk around its axis is 10kgm2. The inertial torque of the second disk around the axis is 50kgm2 and is initially stationary. The second disc is tightened so that it touches the first plate like a car 'clove'. What is the common angular velocity of the system? How much energy is released?
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Answer:
1340
Explanation:
120×2 =140
10×2=20
50×2=100
100×20=2200
2200+140= 1340
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