Question

In a T-20 Cricket match, the average of the
runs scored by two players is 21 and the
average of the runs scored by other 3 players
is 36. The average of the runs scored by these
five players will be:
​

Answer 1

Answer:

Ascending order the data is,

6,8,10,10,15,15,15,50,80,100,120

Sum of runs =6+8+10+10+15+15+15+50+80+100+120=429

Number of matches =11

Mean=

11

429

=39

Median= Middle value of the data =15

Mode= Most occuring observation of the data =15 (3 times)

Three are not same

Answer 2

• Average by first two = 21
• Average by last three = 36
• Average of all five = ?

⠀

Let's say that Average of all five players is 21 then extra runs made by last three will be left out, & we have to distribute it equally in all the players.

⠀

$\underline{\bigstar\:\textsf{According to the given Question :}}$

$:\implies\sf Average=Assumed\:Average+\dfrac{Altered\:Average}{Total\:People}\\\\\\:\implies\sf Average=21+\dfrac{(36-21) \times 3}{5}\\\\\\:\implies\sf Average = 21 + \dfrac{15 \times 3}{5}\\\\\\:\implies\sf Average = 21 + (3 \times 3)\\\\\\:\implies\sf Average = 21 + 9\\\\\\:\implies\sf Average = 30$

⠀

$\therefore\:\underline{\textsf{Hence, average run of five players are \textbf{30}}}.$