Question

In a T-20 match,the number of sixes hit by gayle is double the number of fours hit by him. he scored 16 runs by running between the wickets. if his final score is 80 runs,find the number of four and six hit by him.

Answer 1

Hey friend...!!!

Let the number of 4s be x
So, number of 6s = 2x
Runs by running = 16
Total score = 80
So,
X + 2x + 16 = 80
3x + 16 = 80
3x = 80 - 16
3x = 64
X = 64/3
X = 21.333
So, number of 4s are 21
And,6s are 21 * 2 = 42

Hope it helps...!!!

Answer 2

Hey there !!

Let X Be the Number of 4

Then Number of sixes will be - 2x

According to the Question -

$6 \times 2x + 4 \times x + 16 = 80 \\ \\ = > 12x + 4x = 64 \: \: ....1)\\ \\ = > 16x = 64 \\ \\ = > x = 4$
Hence He shots 4 Fours

and Number of Sixes = 2 × 4

= 8

⊱ verification ⊰ ➭

Putting x = 4 in Equation 1). to get -


12 × 4 + 4×4 = 64

➭ 48 + 16 = 64

➭ 64 = 64

∵ LHS = RHS

Hope this would helps you !!