Question

In a T-20 match, the number of sixes hit by gayle is double the number of fours hit by him. He scored 16 runs by running between the wickets. If his final score is 80 runs, find the number of fours and sixes hit by him

Answer 1

Hey

Let the number of fours hit by him be x


So , runs made by him by fours = 4x

number of sixes hit by him

= double the number of fours = 2x .

So , runs made by him.by sixes = 6 * 2x = 12x


Run made by running between the wickets = 16

Now,

Total runs

= 4x + 12 x + 16


= 16x + 16

= 16 ( x + 1 )

And given that ,

he made total 80 runs .

So,


16 ( x + 1 ) = 80

=> x + 1 = 80 / 16

=> x + 1 = 5


= x = 4

Number of fours =4

number of sixes = 4 * 2


= 8



thanks :)

Answer 2

no. of fours is 4
no. of sixes is 8