In a team of four wrestlers, the average weight is increased by 5kg when one of the wrestler weighing 90kgs leaves the team and a new wrestler joins. Find the weight of new wrestler who joined the team.
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1
Since one of the wrestlers weighs 90 kgs; lets have the weights of the other wrestlers as b, c and d. Also, let X be the average weight. Let us also assume the weight of the new person joining in be = z
In first case, we have average weight X = (90 + b + c + d)/4 --------------- (i)
In the second case, we have average weight X + 5 = (z + b + c + d)/4
or
X = -5 + (z + b + c + d)/4------------------------------------------------------------- (ii)
Equating (i) and (ii), we get the following:
(90 + b + c + d)/4 = -5 + (z + b + c + d)/4
Solving this, we get z = 110kgs.
So the weight of the new wrestler is 110kgs
In first case, we have average weight X = (90 + b + c + d)/4 --------------- (i)
In the second case, we have average weight X + 5 = (z + b + c + d)/4
or
X = -5 + (z + b + c + d)/4------------------------------------------------------------- (ii)
Equating (i) and (ii), we get the following:
(90 + b + c + d)/4 = -5 + (z + b + c + d)/4
Solving this, we get z = 110kgs.
So the weight of the new wrestler is 110kgs
Answered by
2
Number of wrestlers = 4
increase in average weight = 5 kg
increase in sum total of weights of 4 wrestlers = 4 * 5 = 20 kg
so weight of new wrestler - weight of wrestler leaving = 20 kg
Weight of the new wrestler = 90 kg + 20 kg = 110 kg.
increase in average weight = 5 kg
increase in sum total of weights of 4 wrestlers = 4 * 5 = 20 kg
so weight of new wrestler - weight of wrestler leaving = 20 kg
Weight of the new wrestler = 90 kg + 20 kg = 110 kg.
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