In a temple premises the angle of elevation to the top of chariot from a point 30 away from the foot of the chariot on the ground is 30 degree. Find the height of the chariot
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Answer:
Step-by-step explanation:
let AB be the height of chariot(h)
distance between the foot and the point=30m
∠C=30°
so,
tanC=AB/BC
tan30°=AB/30
1/√3=AB/30
10√3=AB
SO THE HEIGHT OF CHARIOT IS 10√3M
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in temple premises the angle of elevation to thetop of chariot from a point 30m away from the foot of chariot on ground is 30°.find the height of the chariot
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