Question

in a tennis competition, 128 players were selected for a series of knockout rounds. in each round the losers were eliminated and the winners reached the next round. how many players moved to the next round after 4th round? express this number in the exponential notation in terms of the initial number of players.​

Answer 1

Answer:

The number of players in first round=

$128 = {2}^{7}$

Second round

$= {2}^{6}$

Third round

$= {2}^{5}$

Fourth round

$= {2}^{4}$

Hence players in fourth round are

${2}^{4} \\ \\ = 2 \times 2 \times 2 \times 2 \\ \\ = 16 \: players$

$\rule{200pt}{5pt}$

Hope it helps you from my side

:)

Answer 2

Answer:

Hence players in fourth round are

2^4 = 2×2×2×2 = 16 players.

$thanks$