Math, asked by ramansandhursm7811, 1 year ago

In a tennis open tournament 71 persons have signed up for elimination rounds. all players are to be paired up for the first round, but because 71 is an odd number one player gets a bye, which promotes him to the second round, without actually playing in the first round. the pairing continues on the next round, with a bye to any player left over. if the schedule is planned so that a minimum number of matches are required to determine the champion, the number of matches which must be played is (a) 71 (b) 70 (c) 69 (d) 36

Answers

Answered by diwadeep
0
i think 36 is correct option (b)
Answered by throwdolbeau
1

Answer:

The correct option is B. 70

Step-by-step explanation:

  • 1st round :

Matches = 71 - 1 = 70/2 = 35 and 35 winners

Bye given = 1

  • 2nd round :

Matches = 18 and 18 winners

  • 3rd round :

Matches played = 9 and 9 winners

  • 4th round :

Matches played = 4 and 4 winners

Bye given = 1

  • 5th round :

Matches played = 2 and 2 winners

Bye given = 1

  • 6th round :

Matches played = 1 and 1 winner

Bye given = 1

  • 7th round :

Matches played = 1 and 1 winner

So, Total number of matches to be played = 35 + 18 + 9 + 4 + 2 + 1 + 1

                                                                          = 70

Hence, The correct option is B. 70

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