Question

In a test, A got 45% of the total marks of 400. B's marks are one-third more than A's
marks. C got 22 marks less than B. D got 12 marks more than the average marks of A,
B and C. How many among A, B, C and D got less than 58% of the total marks?
a) 3
b) 0
c) 2
d) 1​

Answer 1

Answer:

from the above explanation and question asked the answer is c) 2

Answer 2

The correct answer is option(a) 3

GIVEN

In a test, A got 45% of the total marks of 400. B's marks are one-third more than A's marks. C got 22 marks less than B. D got 12 marks more than the average marks of A,B and C.

TO FIND

How many among A, B, C and D got less than 58% of the total marks?

SOLUTION

We can simply solve the above problem as follows;

Total marks of test = 400

Percentage of marks A got = 45%

Marks of A = 45% 400 = 0.45 × 400 = 180

Marks of B = One third more than A.

Marks of B = (1/3 of 180) + 180 = 240.

Marks of C = 240-22 = 218

Marks of D = 180 + 12 = 192

Percentage marks of B = (240/400)× 100 = 60%

Percentage marks of C = (218/400) × 100 = 54.5%

Percentage marks of D = (192/400) × 100 = 48%

Among A, B, C, and D, 3 got less than 58% marks.

Hence, The correct answer is option(a) 3

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