Math, asked by Hvgtech8212, 1 year ago

in a test called acsat, the average marks of 15 test takers is 240. if the marks of 5 test takers are subtracted, the average marks decreases by 40. what is the average marks of 5 test takers?

Answers

Answered by TooFree
74

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Here is the solution:

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Find the total marks of all the 15 test takers:

Average = 240

Total = 240 x 15 = 3600


Find the total marks of the 10 test takers, excluding the 5 of them:

Average = 240 - 40 = 200

Total = 200 x 10 = 2000


Find the total of the 5 excluded test-takers:

Total of the 5 = 3600 - 2000 = 1600


Find the average of the 5 test-takers:

Average = 1600 ÷ 5 = 320 marks


Answer: The average mark of the 5 test takes is 320.

Answered by hiteshgyanchandani6
3

Total marks for 15 students = 240 * 15 = 3600

Avg marks for 10 students = 240 - 40 =200

Total marks for 10 students = 200* 10 = 2000

Total marks for 5 students = 3600 - 2000 =1600

Avg = 1600/ 5 = 320

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