Biology, asked by flboyantHemm, 8 months ago

In a test cross involving F1 dihybrid flies, more
parental-type offspring were produced than the
recombinant-type offspring. This indicates:
a.
(A) The two genes are located on two
different chromosomes.
b.
(B) Chromosomes failed to separate
during meiosis.
C.
(C) The two genes are linked and present
on the same chromosome.
(D) both of the characters are controlled by more than one gene ​

Answers

Answered by vasantha786
0

Answer:

c) y chromosome

Explanation:

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Answered by bved007
1

Answer:

ANSWER

The linkage is the tendency of closely placed genes on a chromosome to stay together during inheritance (no crossover and independent assortment). Completely linked genes do not show crossover and independent assortment; thereby produce only parental combinations. Linked genes are the genes which are closely located on the same chromosome. This makes option C correct for the given case. Option A is incorrect as genes present on different chromosomes exhibit crossing over to make more recombinant offspring; not linkage. Option B is incorrect as a failure of chromosomes to separate during meiosis results in chromosomal abnormalities. Option D is incorrect as the production of recombinant and parental offspring is determined by presence or absence of crossing over; not by type of inheritance

Explanation:

ANS.1

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