in a test of safety restraint,atest car was slowed from 50m/sec to rest in atime of 0.40s a)what acceleration was this.b)how did tje car travel in this time
Answers
Answered by
34
initial v = 50 m/s
final v = 0m/s
time =0.40s
acceleration = v-u/t
= 0-50/0.40
=-50/0.40=1250m per sec sq
final v = 0m/s
time =0.40s
acceleration = v-u/t
= 0-50/0.40
=-50/0.40=1250m per sec sq
nienu:
how far did the car travel in this time..
Answered by
15
Answer:B
V=50m^s
U=0
T=0.4
=50×0.4+1/2×0.8
=20+25×0.8
=10m
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