Question

In a test paper of 125 questions, Anuj got 72% correct answers and Kanak got 52% correct answers. What per cent is Kanak's correct answers to Anuj's correct answers.​

Answer 1

Hey mate here is your answer:

Given:-

$72\% \times 125 = anuj \: marks$

$= > \frac{72}{100} \times 125 = anuj$

$= 90 \: marks$

Also,

$kanak \: = \frac{52}{100} \times 125$

$= 65 \: marks$

What percent is kanak's correct to Anuj's marks?

Solution:

$\frac{kanak \: marks}{anuj \: marks } \times 100\%$

$= > \frac{65}{90} \times 100\%$

$= 72\%$

Required percentage is 72%

Answer 2

Answer:

Hey mate here is your answer:

Given:-

72\% \times 125 = anuj \: marks72%×125=anujmarks

= > \frac{72}{100} \times 125 = anuj=>

100

72

×125=anuj

= 90 \: marks=90marks

Also,

kanak \: = \frac{52}{100} \times 125kanak=

100

52

×125

= 65 \: marks=65marks

What percent is kanak's correct to Anuj's marks?

Solution:

\frac{kanak \: marks}{anuj \: marks } \times 100\%

anujmarks

kanakmarks

×100%

= > \frac{65}{90} \times 100\%=>

90

65

×100%

= 72\%=72%

Required percentage is 72%

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