Math, asked by ArpitVirag, 6 months ago

In a test paper of 125 questions Anuj got 72% correct answers and Kanak got 52% correct answers . What per cent is Kanak's correct answers to Anuj's correct answers .

Please any body tell​

Answers

Answered by pikachubisht67
0

Answer:

72.222

Step-by-step explanation:

anuj's marks = 72% of 125

= 72*125/100

= 90 questions

kanak's marks = 65(using same method above)

kanaks marks as percentage of anuj's marks

x/100 * 90 = 65

x = 65*100/90

x = 72.222

Answered by viskumar9067
0

Step-by-step explanation:

for kanak 52/100×125

for anuj 72/100×125

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