Math, asked by gauravsinha0788, 2 months ago

In a test paper of 125 questions, Anuj got 72% correct answers
and Kanak got 52% correct answers. What per cent is Kanak's
correct answers to Anuj's correct answers?​

Answers

Answered by yashaswini8039
2

Given total number of questions = 125 Anuj's correct answers = (72/100) × 125 = 90 Kanak's correct answers = (52/100) × 125 = 65 Hence Kanak's correct answers to Anuj's correct answers = (65/90) × 100 = 72.2%

Hope it helps you....

Answered by sabreensayyed678
2

Answer:

20% marks

Step-by-step explanation:

Anuj marks= 72/100 x 125

= 90 marks

kanak marks= 52/100 x 125

= 65 marks

Anuj got 25 marks more than kanak.

percentage of correct answer = 25/125 x 100

= 20%

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