In a test, Run scored 20% and failed by 10 marks, Bala scored 40% in the same test and obtained 10 marks more than the pass mark. Find the maximum marks.
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Let the maximum marks be x.
A/q
20/100x +10 = 40/100× -10
1/5x + 10 = 2/5x - 10
2/5x-1/5x= 10 +10
1/5x = 20
x= 20 ×5
= 100
Therefore, maximum marks= 100
A/q
20/100x +10 = 40/100× -10
1/5x + 10 = 2/5x - 10
2/5x-1/5x= 10 +10
1/5x = 20
x= 20 ×5
= 100
Therefore, maximum marks= 100
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