Question

in a
$in \: a \: triangle abc 2 < a = 3 < b = 6 < 2 calculate < a < b < c$
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Answer 1

Answer:

$let \: 2 < a = 3 < b = 6 < c = k \\ so \: 2 < a = k \\ < a = \frac{k}{2} \\ \\ also \: 3 < b = k \\ < b = \frac{k}{3} \\ \\ also \: 6< c = k \\ < c = \frac{k}{6} \\ \\ using \: \: angle \: sum \: property \\ < a + < b + < c = 180 \\ \frac{k}{2} + \frac{k}{3} + \frac{k}{6} = 180 \\ \frac{3k + 2k + k}{6} = 180 \\ k = 180 \\ so \: < a = \frac{k}{2} = \frac{180}{2} = 90 \\ < b = \frac{k}{3} = \frac{180}{3} = 60 \\ < c = \frac{k}{6} = \frac{180}{6} = 30$

Answer 2

above answer is definitely correct

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