Question

In a thermodynamic process pressure of a fixed
mass of a gas is changed in such a manner that
the gas releases 20 J of heat when 8 J of work was
done on the gas. If the initial internal energy of the
gas was 30 J. then the final internal energy will be
(1) 25 J
(3)18 J
(3) 42 J
(4) 58 J​

Answer 1

Explanation:

Heat energy = work done + internal energy ΔQ = ΔW + Δu……..(1) Given : heat = 20J = ΔQ Work done = 8J = Δw From (1), Δu = 20 – 8 = 12J i.e. change in energy = 12 ∴ 30 – final energy = 12 ∴ final energy = 18J Read more on Sarthaks.com - https://www.sarthaks.com/336921/thermodynamic-process-pressure-fixed-mass-gas-changed-such-manner-that-the-gas-release-20j

Answer 2

Explanation:

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