Question

In a thermodynamie process two moles of a mouatonic ideal gas obeys povo? If temperature of the increases gas from 300k to 400k, then find work done by the gas (where R = universal gas constant of ​

Answer 1

Answer:

Given,

P∝V

−2

n=2

T

1

=300K

T

2

=400K

PV

2

=const. . . . . .(1)

γ=2 (PV

γ

=constant)

The above equation shows that the process is adiabatic process,

The work done in adiabatic process in thermodynamics is given by

W=nR

γ−t

(T

1

−T

2

)

W=nR

2−1

(300−400)

W=−100nR=−2×100R

W=−200R

The correct option is B.