Math, asked by salunkesakshi14, 1 year ago

In a three digit number let the digit in hundreds place be x and that in unit place be y, also the sum of the extreme digits is less than the middle digit by unity then what is The value of Hundred, tens, unit, and three digit number ​

Answers

Answered by arihantjaon042006
10

Answer:

three digit number = 110x+11y+10

Step-by-step expl

Answered by JeanaShupp
10

Answer:  he required three digits number is 110x+11y+10

Step-by-step explanation:

We have given in a three digits number

The hundredth place = x

The tens place = y

Now let the middle term is a

Now as the sum of the extreme digits is less than the middle digit by unity

a= x+y+1

Therefore the number is

100 x + 10 (x+y+1) + y = 100x +10x+10y+10 +y = 110x+11y+10

Hence, the required three digits number is 110x+11y+10

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