Question

In a three digit number let the digit in hundreds place be 'x' and that in unit place be 'y' , also the sum of extreme digits is less than the middle digit by unity then find the number.

Answer 1

Answer:

the required three digits number is 110x+11y+10

Step-by-step explanation:

We have given in a three digits number

The hundredth place = x

The tens place = y

Now let the middle term is a

Now as the sum of the extreme digits is less than the middle digit by unity

a= x+y+1

Therefore the number is

Hence, the required three digits number is 110x+11y+10