Question

in a three digit number ,the digits at the hundreds place is three times the digit at the ones place and the sum of digitis is 15 if the digits are reversed the number is reduced by 396 find the number ​

Answer 1

Answer:

Hope it will help u.......

Answer 2

Let us consider the digit at the ones place is = a

and the digit at the tens place is = b

∴ the number will be =[(100× 3a) + 10b + a]

But according to the question, the number will be :-

3a + b +a =15

= 4a + b = 15  ...(1)

and also according to the question :-

(100× 3a + 10b +a) - ( 100a + 10b +3a) = 396

=301a - 103a = 396

= 198 a= 396      ...(2)

a = 2

now put the value of a in equation (1) :-

4a + b =15

4×2 + b = 15

b = 15- 8= 7

Now let us put the value of b in equation (2) ;-

100× 3×2 + 10×7 + 2

= 600+ 70+2

672

Ans:- The three digit number will be 672.