Question

in a three digit number the hundreds digit is twice the tens digit find the units digit is thrice the tens digit also the sum of digits is 18 find the number ​

Answer 1

Answer:

639

Step-by-step explanation:

let the 100s digit be x

let the tens digit be y

let the units digit be z

it's given that 100s digit is twice the tens digit

x = 2y

and the units digit is thrice the tens digit

z = 3y

sum of the digits is 18

x + y + z = 18

2y + y + 3y = 18

6y = 18

y = 18/6 = 3

x = 2y = 2 × 3 = 6

y = 3

z = 3y = 3 × 3 = 9

therefore the required number is

639

hope you get your answer