in a three digit number unitd digit , tens digit and hundreds digit are in the ratio of 1:2:3. if the difference of the original no. and the number obtained by reversing the digits is 594, find the number.
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let unit digit be x
tens digit be 2x , so its value => 10×2x => 20x
hundreds digit be 3x , so its value => 100×3x => 300x
so , number = 300x+20x+x = 321x
number formed by reversing the digits ,
units digit = 3x
tens digit = 2x => value = 2x × 10 => 20x
hundreds digit => x , its Value => 100×x => 100x
so , the number formed => 123x
according to question ,
321x-123x = 594
198x = 594
x = 594/198 => 3
if x = 3 then , the number = 321x => 321×3 => 963 or the number can be = 123x => 123×3 = 369
hope this helps
any confusion then message me
tens digit be 2x , so its value => 10×2x => 20x
hundreds digit be 3x , so its value => 100×3x => 300x
so , number = 300x+20x+x = 321x
number formed by reversing the digits ,
units digit = 3x
tens digit = 2x => value = 2x × 10 => 20x
hundreds digit => x , its Value => 100×x => 100x
so , the number formed => 123x
according to question ,
321x-123x = 594
198x = 594
x = 594/198 => 3
if x = 3 then , the number = 321x => 321×3 => 963 or the number can be = 123x => 123×3 = 369
hope this helps
any confusion then message me
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