Question

In a three digit number units digit ten's digit and hundred digit are in the ratio 1:2:3.if the difference of original number and the number obtained by reversing the digit is 594 find the number

Answer 1

Solution -

Let x be the unit place, y be the tenth place and z be the hundred place digit.

Therefore, Three digit number = 100z + 10y + x

and reversed number = 100x + 10y + z

Given -

100z + 10y + x - (100x + 10y +z) = 594

99z - 99x = 594

z - x = 6 --------------1

z = 6 + x

Also given 

1 : 2 : 3 = x : y : z

z = 3x

Substitute z = 3x in equation 1

3x - x = 6

2x = 6 

x = 3 

Therefore, z = 6 + x = 6 + 3 = 9

as y = 2x = 2 * 3 = 6

Answer - The three digit numer = 100z + 10y + x = 9 *100 + 10 * 6 + 3 = 963