in a throw of a die find the probability of getting a number between 2 and 6
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4
Total number of possible outcome = 6
[That is 1, 2, 3, 4, 5 and 6 ]
Total number of favourable outcome = 3
[ That is 3, 4 and 5 ]
Find the probability that the number is between 2 and 6:
P(between 2 and 6) = 3/6 = 1/2
Answer: The probability is 1/2
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1
No of favorable outcomes=3
Total no.of outcomes= 6
Probability = no.of favorable outcomes÷ total no.of outcomes
=3/6
=1/2
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