Question

in a throw of a die,find the probability of not getting 4 or 5

Answer 1

the probability is 2/3 ...
by 1-(1+1)/6=1-2/6=4/6=2/3
hope it will help

Answer 2

Let S be the sample space of throwing a die ,

S = {1,2,3,4,5,6 }
n (S)=6

Let A be the event of not getting 4 and 5,

A = { 1,2,3,6 }

n (A)=4

p (A)= n (A)/n (S)
= 4 / 6
=2/3

The probability of die not getting 4 or 5 is 2/3.


Hope it helps you!