Math, asked by Rambha18, 6 months ago

In a throw of dice, what is the probability of getting a doublet or some number?​

Answers

Answered by Anonymous
1

Step-by-step explanation:

1/6

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Answered by ummeayeman594
2

Ans: 1/6

Step-by-step explanation:

probability of getting a doublet = { (1,1) , (2,2) , (3,3) , (4,4) , (5,5) , (6,6) } = 6

p(a) =  \frac{n(a)}{n(s)}  \\  =  \frac{6}{36}  \\  =  \frac{1}{6}

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