Question

In a tournament 14 teams play league matches. if each team plays against every other team once only then how many matches are played ?

Answer 1

Formula = n (n -1) / 2

n = 14, n-1 = 14-1 = 13

= 14 X 13 / 2
= 7 X 13 = 91

Answer 2

Given:

There are 14 teams.

Each team will play against every other team.

To Find:

The number of matches each team has to play.

Explanation:

If there are N team. Then N team will have to play against (N - 1) team.

We need two teams to play against each other. If Team A plays against Team B, it is the same game as Team B plays against Team A. We need to count it as once and not twice. So we need to halve it .

Formula:

$\text{Total games played = } \dfrac{N(N-1)}{2}$

Solution:

Find the number of matches:

$\text{Total games played = } \dfrac{N(N-1)}{2}$

$\text{Total games played = } \dfrac{14(14-1)}{2}$

$\text{Total games played = } 91$

Answer: There will be a total of 91 matches played.