Question

In a town 40% of the population read newspaper 'A', 30% read newspaper 'B', 10% read newspaper 'C'. It is found that 5% read both 'A' and 'B'; 4% read both 'A' and 'C'; and 3% read both 'B' and 'C'.Also, 2% of the people read all three newspapers. Find the probability that a person chosen at random from the town. Reads only "A and B"?

Answer 1

population that read newspaper=40%

population that read newspaper A=40%

population that read newspaper B=30%

population that read newspaper c=10%

population that read news paper A and B=5%

population that read newspaper A and C=4%

population that read newspaper B and C=3%

population that read all newspaper=2%

probability that a person will chose at a random reads only A and B is

now we will add all those probabilities in which A or B or both A and B are present

0.05(A and B)+0.04(A and c)+0,03(B and C)+0.02(All)+0.3(B)+0.4(A)=0.82=82/100

Answer 2

Answer:

Step-by-step explanation: