Question

In a town 45% read magazine A, 55% read magazine B, 40% read magazine C, 30% read magazine A and B, 15% read magazine B and C, 25% read magazine C and A, 10% read all the three magazines. Find what percentage does not read any magazine. What percentage reads exactly two of the magazines?​

Answer 1

Answer:

Total population in a town (U)= 100

Number people who read magazine A = n(A)=45

Number people who read magazine B = n(B)=55

Number people who read magazine C = n(C)=40

n(AnB) = 30,

n(BnC) = 15 ,

n(CnA) = 25 and

n(AnBnC) = 10 ,

we know that,

n(AUBUC) = n(A)+n(B)+n(C)-n(AnB)-n(BnC)-n(CnA) + n(AnBnC)

= 45+55+40-30-15-25+10

= 80

i )Percentage of people who doesn't read any magazine = U - n(AUBUC)

= 100 - 80

= 20%

ii ) percentage of people who reads exactly two of the mmagazine = 20 + 15 + 5

= 40%

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