Math, asked by jackjill22, 1 year ago

In a town 80% of the population are adults of which
the men and women are in the ratio of 9:7 respec-
tively. If the number of adult women is 4.2 lakhs, what
is the total population of the village?
a) 12 lakhs b) 9.6 lakhs c) 9.8 lakhs
d) 11.6 lakhs e) 10 lakhs​

Answers

Answered by SwaGduDe
6

Answer .

The total population of the village is 12 lakhs .

Solution.

Given that % of adult population of the village is 80% and population of women is 4.2 lakhs .Ratio of population of men and women is 9:7 respectively.

_______________________________

Let the population of men as x

x : 4.2 = 9:7

 \frac{x}{4.2}  =  \frac{9}{7 } \\

x =  \frac{9 \times 4.2}{7 }  \\

x = 5.4

So men population = 5.4 lakhs .

Now total adult population = men + women

Total adult population = 5.4 +4.2

= 9.6 lakhs.

Now given that% of adult population is 80% ,so total population will -

total \: population \:  =  \frac{9.6 \times 100}{80}  \\

Total population = 12 lakhs

Answered by swrpb007
0

Answer:12 lakh

Step-blet the number of adult men be N.  

Then, ratio of the numbers of adult men and adult women

9 : 7 = N : 4.2

⇒ N = (9/7) x 4.2 = 5.4 Lakh

Total adult population = 4.2 + 5.4 = 9.6 lakh.

If the population of the town be M Lakh,  

then, 80M/100 = 9.6

⇒ M = (9.6 x 100)/80 = 12 lakh

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