In a town, each of the 60% of families has a
laptop, each of the 30% of families has a computer
and each of the 15% of families has both a laptop
and a computer. In all, there are 10800 families in
the town. How many families in the town do not
have a laptop or a computer?
1. 2600
2. 2850
3. 2900
4. 2650
5. 2700
Answers
Answered by
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(1). 2600 is the ans
shivam9238:
say
Answered by
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Answer:
2700
Step-by-step explanation:
According to the concept of set theory, we know that n (a U b) = n (a) +n (b) – n (a ∩ b)
So, the % of families having either a laptop or a computer or both
== n (computer U laptop) = n (computer) +n(laptop) –n (computer and laptop)
== 60+30 -15 = 75%
Families having neither a laptop nor a computer = 100 – 75 = 25%
So, required family = 25/100 x 10800 = 2700
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