Question

In a town, each of the 60% of families has a
laptop, each of the 30% of families has a computer
and each of the 15% of families has both a laptop
and a computer. In all, there are 10800 families in
the town. How many families in the town do not
have a laptop or a computer?
1. 2600
2. 2850
3. 2900
4. 2650
5. 2700

Answer 1

(1). 2600 is the ans

Answer 2

Answer:

2700

Step-by-step explanation:

According to the concept of set theory, we know that n (a U b) = n (a) +n (b) – n (a ∩ b)

So, the % of families having either a laptop or a computer or both

== n (computer U laptop) = n (computer) +n(laptop) –n (computer and laptop)

== 60+30 -15 = 75%

Families having neither a laptop nor a computer = 100 – 75 = 25%

So, required family = 25/100 x 10800 = 2700