Question

In a town of 10,000 families, it was found that 40% families buy newspaper A, 20% buy B, 10% buy C, 5% buy A&B, 3% buy B&C, 4% buy A&C. If 2% buy all three newspaper. Find number of families which buy.
(i) A only (ii) B only
(iii) C only (iv) None of A,B,C

Answer 1

i) %A-%AB-%AC

=(40%-5%-4%)of 10,000

=31% of 10,000

=3,100

ii) %B-%AB-%BC

=(20%-5%-3%) of 10,000

=12% of 10,000

=1,200

iii) %C-%AC-%BC

=(10%-4%-3%) of 10,000

=3% of 10,000

=3,000

iv)(100%-%A-%B-%C)

=(100%-40%-20%-10%) of 10,000

=30%of 10,000

=3,000