In a town of 10,000 families it was found that 40% families buy news paper A, 20% families buy news paper B, and 10% families buy news paper C. Also 5% families buy A and B, 3% buy B and C, 4% buy A and C, and 2% buy all the three news papers. Then the number of families which buy exactly one of A, B, C is
4800
5200
5400
6400
Answers
Answered by
3
Answer:
Number of families=10000
n(A)=
100
40×10000
=4000
n(B)=
100
20×10000
=2000
n(C)=
100
10×10000
=1000
n(A∩B)=
100
5×10000
=500
n(A∩C)=
100
4×10000
=400
n(B∩C)=
100
3×10000
=300
n(A∩B∩C)=
100
2×10000
=200
no. of people buy only A, only B & only C=1400+200+3300=4900
Step-by-step explanation:
Answered by
0
Answer:
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Step-by-step explanation:
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