Question

In a town of 10,000 families it was found that 40% families buy newspaper A, 20% families buy newspaper B, 10% families buy newspaper C, 5% families buy A and B, 3% buy B and C and 4% buy A and C. If 2% families buy all the three newspapers. Find

(a) The number of families which buy newspaper A only.

(b) The number of families which buy none of A, B and C.

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Answer 1

Step-by-step explanation:

A =

$\frac{40}{100} \times 10000 = 4000$

40+20+10+5+3+4+2=84% buy newspapers.

16% doesnt buy newspaper.

1600 doesnt buy newspaper