In a town of 10,000 families it was found that 40% families buy newspaper A, 20% families buy newspaper B and 10% families by newspaper C. 5% families buy A and B, 3%, buy B and C and 4% buy A and C. If 2% families buy all the three newspapers, find the no of families which buy(1) A only (2) B only (3) none of A, B and C (4) exactly two newspapers (5) exactly one newspaper (6) A and C but not B (7) at least one of A, B, C. What is the importance of reading newspaper?
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In a town of 10,000 families it was found that 40% families buy newspaper A, 20% families buy newspaper B and 10% families buy newspaper C. 5% families buy A and B,3% buy B and C and 4% buy A and C. If 2% families buy all the three news papers, find the number of families which buyAA onlyBB onlyC None of A, B and C.
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Number of families=10000
n(A)=
100
40×10000
=4000
n(B)=
100
20×10000
=2000
n(C)=
100
10×10000
=1000
n(A∩B)=
100
5×10000
=500
n(A∩C)=
100
4×10000
=400
n(B∩C)=
100
3×10000
=300
n(A∩B∩C)=
100
2×10000
=200
no. of people buy only A, only B & only C=1400+200+3300=4900.............marks as brain list
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