Math, asked by thoragnarok, 20 days ago

In a town of 10,000 families, it was found that 40% of families buy newspaper A, 20% families buy newspaper B and 10% families buy newspaper C, 5% families buy newspapers A and B, 3% families buy newspapers B and C, 4% families buy newspapers A and C. If 2% of the families buy all the three newspapers, find the number of families which buy (i) A only (ii) None of A, B and C (iii) at least one of A, B or C (iv) Exactly one of A, B or C.

Answers

Answered by mamtameena18480
0

Step-by-step explanation:

Answer

Number of families=10000

n(A)=

100

40×10000

=4000

n(B)=

100

20×10000

=2000

n(C)=

100

10×10000

=1000

n(A∩B)=

100

5×10000

=500

n(A∩C)=

100

4×10000

=400

n(B∩C)=

100

3×10000

=300

n(A∩B∩C)=

100

2×10000

=200

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