Question

in a town of 10,000families it was found that 40 percentage of families buy newspaper a 20% families buy newspaper b 10%families by newspaper c 5% families by newspaper a and b 3%buy b and c and 4% buy aand c if 12% families buy all the three newspaper find 1. the number of families which buy newspaper a only 2. the number of families which buy none of a,b,c​

Answer 1

Answer:

Step-by-step explanation:

The question is wrong

As

n(A intersectionB) = 5% = 500

AND n(A intersection B intersection C)= 12% = 1200

Which is not possible