In a town of 20,000 families it was found that 40% familie
newspaper A, 20% families buy newspaper B and 10% families
newspaper C, 5% families buy A and B, 3% buy B and C and 4%b
and C. If 2% families buy all the three newspapers, then the number
families which buy A only is:
Answers
Answered by
69
Answer:
Step-by-step explanation:
Number of families=20000
n(A)=
40×20000/100
=8000
n(B)=
20×20000/100
=4000
n(C)=
10×20000/100
=2000
n(A∩B)=
5×20000/100
=1000
n(A∩C)=
4×20000/100
=800
n(B∩C)=
3×20000/100
=600
n(A∩B∩C)=
2×20000/100
=400
no. of people buy only A, only B & only C=n(A)-[n(A^B)+n(A^C)-n(A^B^C)]
=8000-(1000+800-400)
=8000-1400
=6600
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Answered by
2
Answer:
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