Question

In a town of 20,000 families it was found that 40% familie
newspaper A, 20% families buy newspaper B and 10% families
newspaper C, 5% families buy A and B, 3% buy B and C and 4%b
and C. If 2% families buy all the three newspapers, then the number
families which buy A only is:
​

Answer 1

Answer:

Step-by-step explanation:

Number of families=20000

n(A)=

40×20000/100

​

=8000

n(B)=

20×20000/100

​

=4000

n(C)=

10×20000/100

​

=2000

n(A∩B)=

5×20000/100

​

=1000

n(A∩C)=

4×20000/100

​

=800

n(B∩C)=

3×20000/100

​

=600

n(A∩B∩C)=

2×20000/100

​

=400

no. of people buy only A, only B & only C=n(A)-[n(A^B)+n(A^C)-n(A^B^C)]

=8000-(1000+800-400)

=8000-1400

=6600

Hope this will be helpful to you and please mark my answer as the brainleast answer.plzplz plz plz.........

Answer 2

Answer:

Step-by-step explanation: