In a town the population was 8000 in 1 year male population increased by 10% and female population increased by 8% but the total population increased by 9% the number of males and the town is
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9% of 8000 = 8000 × 9/100
= 720
now let men were x
therefore women were 8000-x
now increase in men are , 10%of x
= 10x /100
= x /10
now increase in women are , 8%of (8000 - x)
= 8/100(8000-x)
= 64000 /100 - 8x /100
= 640 - 2x / 25
now, x /10 + 640 - 2x / 25 = 720
x /10 - 2x / 25 = 720 -640
25x - 20x /250 = 80
5x = 80 * 250
x = 80 * 250 /5
x = 4000
therefore 4000 males were
4000 women were
increased males = 400
increased females =320
= 720
now let men were x
therefore women were 8000-x
now increase in men are , 10%of x
= 10x /100
= x /10
now increase in women are , 8%of (8000 - x)
= 8/100(8000-x)
= 64000 /100 - 8x /100
= 640 - 2x / 25
now, x /10 + 640 - 2x / 25 = 720
x /10 - 2x / 25 = 720 -640
25x - 20x /250 = 80
5x = 80 * 250
x = 80 * 250 /5
x = 4000
therefore 4000 males were
4000 women were
increased males = 400
increased females =320
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